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n HCL = 0,1*100= 10 mmol
n NH3 = 0,3*50 = 15 mmol
reaksinya :
HCL+NH3------> NH4CL
10 15
10 10 10
----------------------------------
-- 5 10
Reaksi diatas itu pakai mula-breaksi-sisa. Disitu sisa nya basalemah, jadi pakai rumus penyangga.
[OH-]=kb.nb/ng
[OH-]=10-5.5/10
[OH-]=0,5.10^-5=5.10^-6
Lalu masukin ke rumus pOH=-log[OH-]
pOH=-log5.10^-6
pOH=6-log5
pH+pOH=14
pH+6-log5=14
pH=14-(6-log5)
pH=8+log5