December 2018 1 30 Report
\frac{ (-1)^{n}(2n-2)!n(n-2) }{ 2^{2n} n!}
Jeśli ktoś zdoła mi to przekształcić do postaci:
\frac{ (-1)^{n}(2n)! }{ 2^{2n+1} n!}

będę bardzo wdzięczna.
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