August 2018 3 12 Report
Jeśli ktoś jest mocny z matmy to proszę o rozwiązanie ; )
a + b + c + 2,5a + 2b - 0,5a
a + 3b + 14a- b
5z-4z
6x - x
i następne
3x - 2 - 2x + 5 + 4x gdy x = 12
3a - b + 5a+ 2b - 6 gdy a = 2 i b=2
x + 2y - 3 y - 3z + 5z - x gdy x = 5 y = 8 z = 6
3 ( x - 4z + y + 4x - z +2y) gdy x = 1 y = 2 z=12
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