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= (3√2+√3)(√3+√2) ÷ (√3-√2)(√3+√2)
= (3√6+3.2+3+√6) ÷ (3-2)
= (3√6+6+3+√6) ÷ 1
= 9 + 4√6
³log 125
=³log 5³
=3 ³log5
=3p