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(2x+15)/9 > 1/5(x-1) + x/3 //*9
2x+15 > (9/5)* (x-1) + 3x
14x < 94/5
x<94/90
x<47/45
i druga część
x+1/x<1
(x+1)/x - 1 <0
(x+1 - x)/x<0
1/x<0
x<0
z 1 i 2 x należy (-inf;0)