Question

jawablah soal di atas beserta caranya​

Answer 1

Penjelasan dengan langkah-langkah:

1.

[tex] \frac{ {8}^{3} \times 4^{5} }{ {2}^{3} } [/tex]

[tex] \frac{ ({2}^{3} {)}^{3} \times ({2}^{2} {})^{5} }{ {2}^{3} } [/tex]

[tex] \frac{ {2}^{9} \times {2}^{10} }{ {2}^{3} } [/tex]

[tex] {2}^{9 + 10 - 3} [/tex]

[tex] {2}^{16} [/tex]

2. 7✓2+✓98-✓242

= 7✓2+✓49x2-✓121x2

=7✓2+7✓2-11✓2

= 14✓2-11✓2

=3✓2

3.

[tex] {x}^{2} - 4x + 4 = 0[/tex]

pxq = 4

p+q =-4

(x-2)(x-2) =0

x-2 = 0

x = 2

hp (2,2)

4.

[tex] {2x}^{2} + 5x + 2 = 0[/tex]

a=2, b=5, c= 2

= -b +-✓b^2-4ac/2a

= -5+-✓5^2-4x2x2/2x2

= -5+-✓25-16/4

= -5+-✓9/4

=-5+-3/4

=-5+3/4

=2/4

=1/2

atau =-5-3/4

=-8/4

=-2

hp(1/2,-2)

5.

[tex] {x}^{2} + 6x - 16 = 0[/tex]

x^2+6x=16

x^2+6x+9 = 16+9

x^2+6x+9= 25

(x+3)2=+-5

x+3= 5 atau x+3=-5

x=5-3 atau x=-5-3

x=2 atau x = -8