Question

Jawablah nomor 40 beserta anaknya saja! Disertakan jg dengan langkah penyelesain yah

Makasih ^^

Answer 1

Verified answer

DINAMIKA

m = 6 kg
F = 60 N
α = 60°

(1) gaya penggerak
Fx = F cos α
Fx = 60 cos 60°
Fx = 60 • ½
Fx = 30 N ✔️

(2) percepatan jika bidang licin
Fx = m a
30 = 6 a
a = 30/6 = 5 m/s² ✔️

(3) gaya normal
N + Fy = w
N = w - Fy
N = m g - F sin α
N = 6 • 10 - 60 • ½√3
N = 60 (1 - ½√3) ✔️

(4) koefisien gesekan kinetis, jika GLB (a = 0)
Fx - fₖ = 0
Fx = μₖ N
μₖ = Fx / N
μₖ = 30 / [60 (1 - ½√3)]
μₖ > 0,5 ❌


jawaban [A] 1,2,3 benar.