Question

Jawaban no.1,2,5,dan 7 apa cpt ya dan pake cara ok

Answer 1

1)
SPQ sudut berpelurus = 180°
a)
3x + x + 80° = 180°
4x = 100°
x = 25°
b)
3x = 3 . 25 = 75°
c) PQR = segitiga = 180°
x + PQR + 80° = 180°
PQR = 100° - 25°
PQR = 75°

2) Itu kan sebuah segitiga, jumlah sudut 180°

x + 85° + 35° = 180°
x = 180° - 120° = 60°

7)
K = AB + BC + CD + AD
54 = 2.AB + 17 + 17
54 = 2.AB + 34
2.AB = 20
AB = AD = 10

Phytagoras :
OB²
= AB² - OA²
= 10² - 6²
= 100 - 36
OB² = 64 ----> OB = √64 = 8 cm

a) BD = 2.OB = 2 x 8 = 16 cm
b) OC² = BC² - OB²
= 17²- 8²
= 289 - 64
OC² = 225 ---> OC = √225 = 15 cm

AC = OC + OA = 15 + 6
= 21 cm

c) L = ½ . AC . BD
= ½ . 21 . 16
= 21 x 8
= 162 cm²