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Verified answer
DINAMIKA ROTASI• Momen gaya
berat batang
w = m g
w = 4 • 10 = 40 N
berat beban
w₁ = m₁ g
w₁ = 2,5 • 10 = 25 N
Resultan momen gaya di O
Στₒ = Σ(F d)
Στₒ = - F d₁ + w d₂ + w₁ d₃
Στₒ = -200 • 5/100 + 40 • 25/100 + 25 • 50/100
Στₒ = -10 + 10 + 12,5
Στₒ = 12,5 Nm ✓
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