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Titik potong dengan sb- x ⇒ y = 0, maka3 - x² = 0 ⇒ (√3-x)(√3+x) = 0 ⇒ x1 = -√3 atau x2 = √3
Titik P(-√3,0) dan Q(√3,0)
Titik potong dengan sb-y ⇒ x = 0, maka
y = 3 - 0² = 0 ⇒ titik R(0,3)
PR = √((-3)²+3²) = √12 = 2√3
QR = √((√3)²+3²) = √12 = 2√3
PQ = √(√3+√3)²+0²) = √12 = 2√3
Jadi ΔPQR sama sisi, maka a = √3