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m = 2.400 kg
Vo = 60 km/jam
mobil di reh Hingga berhenti
S = 45 m
Penyelesaian :
Vo = (60x1000)/3.600
= 16,667 m/s
a. Kecepatan mobil saat di rem= 0 m/s
atau Vo = 0 m/s
b. Vt² = Vo² + 2 x a x s
16,67² = 0 + 2 x a x 45
277,8334 = 90 x a
a = 277,8334/90
a = 3,08 m/s²
c. F = m x a
= 2.400 x 3,08
= 7.408,889 N
d. a = (Vt-Vo)/t
3,08 = (0-16,67)/t
3,08xt = -16,67
t = -16.67/3,08
t = - 4,38 s (tnda mines menunjukkan perlambatan)
jadi t = -4,38 s