Question

Jawab dengan benar ya
soalnya yg sy lingkari digambar

yg gambar ke 1 merupakan contoh penyelesaian dari soal no 1 bagian A

Answer 1

Nomer 1 sdh kan ....
2b) int 6x sin3x dx
misal u = 6x -----> du = 6 dx
dv = sin3x dx ----> v = int sin(3x) dx = -1/3 cos(3x)

= uv - int v du
= 6x(-1/3 cos(3x)) - int -1/3 (6) cos(3x) dx
= -2x cos(3x) + int 2cos(3x) dx
= -2x cos(3x) + 2/3 sin(3x) + C

3) int 9x^2 cos(3x) dx
misal u = 9x^2 -----> du = 18x dx
dv = cos(3x) dx -----> v = int cos(3x) dx = 1/3 sin(3x)

= uv - int udv
= 9x^2 (1/3) sin(3x) - int 1/3 (18x) sin(3x) dx
= 3x^2 sin(3x) - int 6x sin(3x) dx
partialkan lagi bagian int 6x sin(3x) dx
misal u = 6x -----> du = 6 dx
dv = sin(3x) dx ----> v = int sin(3x) dx = -1/3 cos(3x)
so,
int 6x sin(3x) dx = uv - int  v du
int 6x sin(3x) dx = 6x(-1/3)cos(3x) - int (-1/3) 6 cos(3x) dx
int 6x sin(3x) dx = -2x cos(3x) + int 2cos(3x) dx
int 6x sin(3x) dx = -2xcos(3x) + 2/3 sin(3x) + C
so,
int 9x^2 cos(3x) dx
= 3x^2 sin(3x) - (-2xcos(3x) + 2/3 sin(3x)) + C
= 3x^2 sin(3x) + 2x cos(3x) - 2/3 sin(3x) + C

Answer 2

Semoga membantu.. ^_^