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Verified answer
Rumus yg diperlukanrangkaian paralel
1/Rp = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
rangkaian seri
Rs = R1 + R2 + ... + Rn
V = I x R
maka dlm soal ini
rangkaian paralel (mencakup R2 dan R3)
1/Rp = 1/R2 + 1/R3
= 1/2 + 1/2
1/Rp = 1/1
Rp = 1 ohm
rangkaian total (dg rumus seri) ( mencakup Rp yg didapat di atas dan R1)
Rtot = 5 ohm + 1 ohm
Rtotal = 6 ohm
maka
V = I x R
12 V = I x 6 ohm
12 V : 6 ohm = I
2 A = I
maka kuat arus pd rangkaian adl 2 A