Sebuah mobil berjln di tikungan dg jari2 100m dg kecpatan 90km/jam. brp percepatan sentripetal?? caranya gmn plisss
anggasvara
Dik: v = 90 km/jam = 25 m/s r = 100 m as = ...?
Jawab:
as = v² / r as = (25)² / 100 as = 625 / 100 as = 6,25 m/s²
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diahh
ini gimana sih caranya minta tolong dong : sbuah benda massanya 200g diikat dg tali 1m,kmudian diputar horizontal hingga bergerak melingkar beraturan. dalam wkt 10 s terjadi 50 putaran. berapa kelajuan linear dan percepatan sentripetalnyaa?
anggasvara
m = 200 g
r = 1 m
10 s = 50 putaran , maka 1 s = 5 putaran (5rad/s)
w = 5rad/s
Kelajuan linear (v):
w = v/r
5 = v/1
v = 5 m/s
percepatan sentripetal:
as = v^2 / r = 5^2 / 1 = 25 m/s^2
Kurang lebih seperti itu, silakan dikoreksi jika ada kesalahan perhitungan.
v = 90 km/jam = 25 m/s
r = 100 m
as = ...?
Jawab:
as = v² / r
as = (25)² / 100
as = 625 / 100
as = 6,25 m/s²