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m = 1250 kg
v₀ = 72 km/j = 20 m/s
v₁ = 36 km/j = 10 m/s
Ditanyakan :
F hambat = .... ?
Jawab :
Δv = v₁-v₀
Δv = 10 - 20
Δv = -10 m/s
**************************
a = Δv/Δt
a = -10/5
a =-2 m/s²
Jadi perlambat mobil sebesar -2m/s² .
F = m .a
F = 1250 . (-2)
F = -2500 N
Tanda minus (-) dimaksudkan karena F melawan arah kecepatan , atau bisa disebut sebagai Gaya perlambatan seperti pada soal .