jakie pole ma prostokąt którego obwód jest równy 16x-4 a jeden bok wynosi 3x
L=16x-4
a=3x
L=2(a+b)
16x-4=2(3x+b)
16x-4=6x+2b
10x-4=2b
b=5x-2
P=ab
P=(5x-2)3x
P=15x²-6x
P=3x(5x-2)
ob=2a+2b=16x-4
6x+2b=16x-4
2b=10x-4
P=a*b=3x*(5x-2)=15x^2-6x
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
L=16x-4
a=3x
L=2(a+b)
16x-4=2(3x+b)
16x-4=6x+2b
10x-4=2b
b=5x-2
P=ab
P=(5x-2)3x
P=15x²-6x
P=3x(5x-2)
ob=2a+2b=16x-4
6x+2b=16x-4
2b=10x-4
b=5x-2
P=a*b=3x*(5x-2)=15x^2-6x