Jakie jest pole (m2) i obwód koła o średnicy 6.60 m i promieniu 3.30 m ?
r=3,3 m
P=π r²
P=π*10,89
P=10,89 π m²
---------------------------------------------------------
L=2π r=
L=2π*3,3
L=6,6 π m
============================================================
P = π R^2
P = 3,14 * (3,30)^2
P = 3,14 * 10,89
P = 34,19 m^2
L = 2 πR
L = 2 * 3,14 * 3,30
L = 6,28 * 3,30
L = 20,72 m
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r=3,3 m
P=π r²
P=π*10,89
P=10,89 π m²
---------------------------------------------------------
L=2π r=
L=2π*3,3
L=6,6 π m
============================================================
P = π R^2
P = 3,14 * (3,30)^2
P = 3,14 * 10,89
P = 34,19 m^2
L = 2 πR
L = 2 * 3,14 * 3,30
L = 6,28 * 3,30
L = 20,72 m