jaki pole ma prostokat którego obwód jest równy 16x-4 a jeden bok wynosi 3x
a =3x - jeden bok prostokąta
b - drugi bok prostokąta
L(obwód) =16x-4
L = 2(a+b)
2(3x+b) =16x-4
2(3x+b) = 2(8x-2) I:2
3x+b =8x-2
b =8x-3x-2
b =5x-2
----------
P =a*b
P =3x(5x-2)
P =15x^2 -6x
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a =3x - jeden bok prostokąta
b - drugi bok prostokąta
L(obwód) =16x-4
L = 2(a+b)
2(3x+b) =16x-4
2(3x+b) = 2(8x-2) I:2
3x+b =8x-2
b =8x-3x-2
b =5x-2
----------
P =a*b
P =3x(5x-2)
P =15x^2 -6x
============