Jaki kąt ostry α jest rozwiązaniem równania: tg(2x-6°)=1 ?
tg(2x-6°)=1
tg(2x-6°)=tg45*
2x - 6* = 45*
2x = 45* + 6*
2x = 51*
x = 51* : 2
x = 25,5* ----- odpowiedź
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
tg(2x-6°)=1
tg(2x-6°)=tg45*
2x - 6* = 45*
2x = 45* + 6*
2x = 51*
x = 51* : 2
x = 25,5* ----- odpowiedź