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Δ=b²-4ac=9+16=25
√Δ=5
y=a(x-x₁)(x-x₂)
a=√2
x₁=(-b-√Δ):2a=-½√2
x₂=(-b+√Δ):2=2√2
postać iloczynowa:
√2(x-2√2)(x+½√2)=0
y=(√2x-4)(√2x+1)
liczymy Δ gdzie a=√2 b=-3 c=-2√2
Δ=b²-4ac
Δ=9+16
Δ=25
√Δ=5
x₁=(-b-√Δ):2a=(3-5):2*√2=-2:2√2=-½√2
x₂=(-b+√Δ):2a=(3+5):2*√2=8:2√2=2√2
postać iloczynowa:
y=a(x-x₁)(x-x₂)
a=√2
y=√2(x-2√2)(x+½√2)
y=(√2x-4)(√2x+1)