jaka jest moc chłopca, którego cięzar wynosi 0,5 kN jeżeli wchodzi on po drabinie na wysokości 10 metrów w czasie 20s.
P=W/t
W=F*s
W=500N*10m=5000J
P=5000J/20s=125W
Q=F= 0,5 kN=500Nh=s=10m
t=20s
P=?
P=F*s/t
P=500N*10m/20s
P=5000J/20s
P=250W
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P=W/t
W=F*s
W=500N*10m=5000J
P=5000J/20s=125W
Q=F= 0,5 kN=500N
h=s=10m
t=20s
P=?
P=W/t
W=F*s
P=F*s/t
P=500N*10m/20s
P=5000J/20s
P=250W