" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
m = 2 kg
T₁ = 20⁰C
T = 60 ⁰C
Cw = 4200 [J/kg × ⁰ C]
Rozw.:
Q = m × Cw × ΔT
Q = m × Cw × ( T - T₁) = 2 kg × 4200 [J/kg × ⁰ C] × (60 ⁰C - 20⁰C) = 336000J
Ew=-------------
K×m
60C-20C=40C
Ilość enrgi potrzebnej do ogrzania ciała: Q=c×m×deltaT
4200j
Q=---------------×2kg×40C=336000J
m×K