Jak wyznaczyć a1 i r w ciągu arytm, jeśli
a) a3+ a5+24 i a3 X a5+135
Korzystamy z wzoru
an = a1 + ( n -1)*r
zatem
a3 + a5 = 24
a3*a5 = 135
mozna zapisać
a1 + 2r + a1 + 4r = 24
( a1 + 2r)*(a1 + 4r) = 135
---------------------------------
2 a1 + 6r = 24 / : 2
a1 + 3r = 12 => a1 = 12 - 3r
( 12 - 3r + 2r)*(12 - 3r + 4r) = 135
(12 - r)*(12 + r) = 135
144 - r^2 = 135
r^2 = 144 - 135 = 9
r = - 3 lub r = 3
================
a1 = 12 - 3*(-3) = 12 + 9 = 21 lub a1 = 12 - 3*3 = 12 - 9 = 3
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Odp.
a1 = 21 , r = - 3 lub a1 = 3, r = 3
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Korzystamy z wzoru
an = a1 + ( n -1)*r
zatem
a3 + a5 = 24
a3*a5 = 135
mozna zapisać
a1 + 2r + a1 + 4r = 24
( a1 + 2r)*(a1 + 4r) = 135
---------------------------------
2 a1 + 6r = 24 / : 2
a1 + 3r = 12 => a1 = 12 - 3r
( 12 - 3r + 2r)*(12 - 3r + 4r) = 135
(12 - r)*(12 + r) = 135
144 - r^2 = 135
r^2 = 144 - 135 = 9
r = - 3 lub r = 3
================
a1 = 12 - 3*(-3) = 12 + 9 = 21 lub a1 = 12 - 3*3 = 12 - 9 = 3
---------------------------------------------------------------------------
Odp.
a1 = 21 , r = - 3 lub a1 = 3, r = 3
======================================