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-(3a-1)=√5*√(a²+1)
-3a+1=√5*√(a²+1) /()²
9a²-6a+1=5(a²+1)
9a²-6a+1-5a²-5=0
4a²-6a-4=0 /:2
2a²-3a-2=0
Δ=9+4*2*2=25
a=1/4*(3-5)=-1/2 v a=1/4*(3+5)=2∉D
2.
Dla a≥1/3
(3a-1)²=5(a²+1)
9a²-6a+1-5a²-5=0
4a²-6a-4=0
a=-1/2∉D v a=2
Odp. a=-1/2 v a=2