Jak obliczyć ten bilans elektronowy
...CH3CH2OH + ...Cr2O72- + ...H+ -> ...CH3COOH + ...Cr3+ + ...H2O
CH3CH2OH + H2O - 4e ----> CH3COOH + 4H+ | x3C2O7 2- + 14H+ + 6e ----> 2Cr 3+ + 7H2O | x2
CH3CH2OH- C jest na -I stopniu utlenienia
CH3COOH- C jest na III stopniu utlenienia
Cr2O7^2- - Cr jest na VI st. utl.
Cr^3+- Cr jest na III st.utl.
Bilans:
14H+ +6e- + Cr2O7^2- -------------->2Cr^3+ +7H2O /*2
H2O+CH3CH2OH------------->CH3COOH + 4H+ + 4e- /*3
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28H+ + 2Cr2O7^2- +3H2O+3CH3CH2OH---->4Cr^3+ +12H+ +3CH3COOH + 14H2O(skracamy
16H+ 2Cr2O7^2- + 3CH3CH2OH--------->4Cr^3+ + 3CH3COOH + 11H2O
Teraz uzupełniamy głowne równanie:
3CH3CH2OH+2Cr2O7^2- + 16H+--------->3CH3COOH +4Cr^3+ + 11H2O
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CH3CH2OH + H2O - 4e ----> CH3COOH + 4H+ | x3
C2O7 2- + 14H+ + 6e ----> 2Cr 3+ + 7H2O | x2
CH3CH2OH- C jest na -I stopniu utlenienia
CH3COOH- C jest na III stopniu utlenienia
Cr2O7^2- - Cr jest na VI st. utl.
Cr^3+- Cr jest na III st.utl.
Bilans:
14H+ +6e- + Cr2O7^2- -------------->2Cr^3+ +7H2O /*2
H2O+CH3CH2OH------------->CH3COOH + 4H+ + 4e- /*3
___________________________________________________
28H+ + 2Cr2O7^2- +3H2O+3CH3CH2OH---->4Cr^3+ +12H+ +3CH3COOH + 14H2O(skracamy
___________________________________________________
16H+ 2Cr2O7^2- + 3CH3CH2OH--------->4Cr^3+ + 3CH3COOH + 11H2O
Teraz uzupełniamy głowne równanie:
3CH3CH2OH+2Cr2O7^2- + 16H+--------->3CH3COOH +4Cr^3+ + 11H2O