Question

Jak najszybciej proszę o odpowiedź, z góry dziękuję !

1) Oblicz :

1. - (a + 2b) + (3a + b) - (4a - 2b) =

2. a^{2} + b^{2} - (2a^{2} - b^{2}) + a^{2} - 3b^{2} =

3. (- 1 - a) - (a + 3) + (4 + 2a) =

4. 10 + 3a - b - (2a - 3b) - 10 =

5. (2 - a) - (a - 3) + (4 - 2a) - (1 - a) =

6. (a + 2 )(b + 1) =

7. (a + 3)(a + 4) =

8. (a - 2)(b - 1) =

9. (a - 3)(a - 2) =

10. (a^{2} + 2)(a + 5) =

11. (a - 5)(7 - a^{2}) =

12. (x + 3y)(2x + 4y) =

13. (2a - b)(3a + b) =

14. (a - 2b)(a^{2} - 3b) =

15. (x - 2)(x - 3) - 2x(x + 2) =

16. (3a - 1)(2 - a) - (a + 1)(1 - 2a) =

17. 3b(b - 2) - [9b^{2} - (b - 1)(b + 2)] =

18. (a + 3)(a + 1) + (a + 2)(a + 7) =

19. (3a - 5)(2a + 3) + (6a - 1)(1 - 2a) =

20. (a + 4)(a - 5) - (2a + 3)(5a - 4) - 3(2a + 1) =

21. a(b + 3) - (a + 3)(b - 4) - 2(a + 2b) =

22. (2xy - 6z)(2xy - 6z)(2xy + 6z) =

Answer 1

1. - (a + 2b) + (3a + b) - (4a - 2b) = -a - 2b + 3a + b -4a + 2b = -2a + b

2. a^{2} + b^{2} - (2a^{2} - b^{2}) + a^{2} - 3b^{2} =  a^{2} + b^{2} -2a^{2} + b^{2}) - a^{2} + 3b^{2} = 2a^{2} + 5b^{2}

3. (- 1 - a) - (a + 3) + (4 + 2a) = - 1 - a - a - 3 + 4 + 2a = 0

4. 10 + 3a - b - (2a - 3b) - 10 = 10 + 3a - b - 2a + 3b - 10 = a + 2b

5. (2 - a) - (a - 3) + (4 - 2a) - (1 - a) =2 - a - a + 3 + 4 - 2a - 1 + a = a + 8 

6. (a + 2 )(b + 1) = a+2 * b + 1 = a + 2b + 1

7. (a + 3)(a + 4) = a+3 * a+4 = a + 3a + 4 = 4a + 4

8. (a - 2)(b - 1) = a - 2 * b - 1 = a - 2b - 1 

9. (a - 3)(a - 2) = a-3 * a - 2 = a - 3a - 2 = 2a - 2

10. (a^{2} + 2)(a + 5) = a^{2} + 2 * a + 5 = a^{2} + 2a + 5

11. (a - 5)(7 - a^{2}) = a -5 * 7 - a^{2} = a - 35 - a^{2}

12. (x + 3y)(2x + 4y) = x + 3y * 2x + 4y = 3x * 7y

13. (2a - b)(3a + b) = 2a - b * 3a + b = 6a 

14. (a - 2b)(a^{2} - 3b) = a - 2b * a^{2} - 3b = a - (-1b) * a^{2}

15. (x - 2)(x - 3) - 2x(x + 2) = x-2 * x-3 - 3x - 4x = x - 2x - 3 - 3x - 4x = 8x - 3

16. (3a - 1)(2 - a) - (a + 1)(1 - 2a) = 3a - 1 * 2 - a -a - 1* 1 - 2a = 3a -2 -a -a - 1 -2a = -a - 3

17. 3b(b - 2) - [9b^{2} - (b - 1)(b + 2)] = 4b - 6b - [9b^{2} - b - 1*b+2 ] = -2b - [9b^{2} - b -b + 2] = -2b - 9b^{2} -2b + 2 = -4b + 9b^{2} + 2 

18. (a + 3)(a + 1) + (a + 2)(a + 7) = a+3*a+1 + a+2 * a+ 7 = 4a +1 +   3a + 7 = 7a + 8

19. (3a - 5)(2a + 3) + (6a - 1)(1 - 2a) = 3a - 5 * 2a + 3 + 6a - 1 * 1 - 2a = -7a + 3 + 4a - 1 = -3a + 2

20. (a + 4)(a - 5) - (2a + 3)(5a - 4) - 3(2a + 1) = a+4 * a-5 - 2a -3 * 5a - 4 - 6a - 3 = 5a - 5 - 13a - 4 - 6a - 3 = -14a  - 12

21. a(b + 3) - (a + 3)(b - 4) - 2(a + 2b) = ab + 3a - a - 3* b-4 - 2a + 2ab = 3ab - 3b

22. (2xy - 6z)(2xy - 6z)(2xy + 6z) = 2xy - 6z * 2xy - 6z * 2 xy + 6z = 2xy - 12xyz - 12xyz + 6z = 2xy - 24xyz + 6z

 

Mam nadzieję że jak jest np. a^{2} to znaczy że a jest do potęgi drugiej. :P