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Q= 80 kJ = 80000 J
m1 = m2 = 4kg
Cw = 800 J/kg*C
<delta>T1 = 10*C
Szukane:
<delta>T2 = ?
Rozwiązanie:
Q = m x Cw x <delta>T / : (m x Cw)
<delta>T = Q/m x Cw
<delta>T = 80000J / 4kg x 800
<delta>T = 200*C
<delta>T2 = 200*C + 10*C = 210*C
Odp. Temperatura piasku po podgrzaniu wyniesie 210*C
p.s. nie jestem pewna, czy dobrze ;)