Question

"Tentukan penyelesaian atau akar sistem persamaan berikut!".
1. ½x + 1/5y = 1 dan ⅓x - 1/5y = 4
2. P-1/6 + q = 6 dan p + q-1/4 = 8
3. 3x-1/4 + 2y = 4 dan 2x+2/2 + y = 5
(Yang ada tanda / itu artinya per yaa)
Tolong yang pintar matematika dijawab ya lertanyaan saya dengan jelas + pakai cara.. Itu pointnya udh banyak lhoo.. Tolong dijawab yaa hari senin dikumpulkan pr
Oiya yg digambar itu prnya yg dilingakari saja nomornya

Answer 1

1.
½x + (1/5)y = 1 (x1)
⅓x - (1/5)y = 4 (x-1)
----------------------------
½x + (1/5)y = 1
-⅓x + (1/5)y = -4
----------------------- (-)
(5/6)x = 5
x = 6

½x + (1/5)y = 1
½.6 + (1/5)y = 1
(1/5)y = -2
y = -10

hp (6, -10)

2.
(p-1)/6 + q = 6
(p-1+6q)/6 = 6
p+6q = 37

p + (q-1)/4 = 8
(4p+q-1)/4 = 8
4p+q = 33

p+6q = 37 (x4)
4p+q = 33 (x1)
---------------------
4p+24q = 148
4p+q = 33
-------------------- (-)
23q = 115
q = 5

4p+q = 33
4p+5 = 33
4p = 28
p = 7

hp (7, 5)

3.
(3x-1)/4 + 2y = 4 (x1)
(2x+2)/2 + y = 5 (x2)
-------------------------------
(3x-1)/4 + 2y = 4
2x+2 + 2y = 10
----------------------- (-)
(3x-1)/4 - (2x+2) = -6
(3x-1)/4 - 4(2x+2)/4 = -6
3x-1-8x-8 = -24
-5x-9 = -24
-5x = -15
x = 3

(3x-1)/4 + 2y = 4
(3.3 - 1)/4 + 2y = 4
2 + 2y = 4
2y = 2
y = 1

hp (3, 1)