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Karena G x H / G + B
= 36 / 12 + 2
= 3 + 2
= 6
AB = AE + EF + FB = 1 m + 2 m + 1 m = 4 m
◆Luas Segitiga ABC
⇨ (AB × TC) / 2 = 12 m²
⇨ ( 4 m × TC ) / 2 = 12 m²
⇨ 4 m × TC = 24 m²
⇨ TC = 24 m²/ 4 m
⇨ TC = 6 m
Jadi tinggi atap depan = TC = 6 m