ekamiaww
13) uang ana = x uang asti = y x = 3y x - y = 5000 substitusi 3y - y = 5000 2y = 5000 y = 2500 substitusikan kembali x = 3 (2500) x = 7500 jadi uang ana Rp. 7.500,- dan asti Rp. 2.500,- (c)
14) x + 2y = 0 (x2) --> 2x + 4y = 0 2x - y = 5 (x1) --> 2x - y = 5 _ 5y = -5 y = -1 x + 2y = 0 x + 2(-1) = 0 x = 2 Hp = {(2,-1)} (a)
16) bil pertama = a bil kedua = b a + b = 2 2a + 5 = -1 penyelesaian 2a + 5 = -1 2a = -1 - 5 2a = -6 a = -3 substitusi a + b = 2 -3 + b = 2 b = 2 + 3 b = 5
uang asti = y
x = 3y
x - y = 5000
substitusi
3y - y = 5000
2y = 5000
y = 2500
substitusikan kembali
x = 3 (2500)
x = 7500
jadi uang ana Rp. 7.500,- dan asti Rp. 2.500,- (c)
14) x + 2y = 0 (x2) --> 2x + 4y = 0
2x - y = 5 (x1) --> 2x - y = 5 _
5y = -5
y = -1
x + 2y = 0
x + 2(-1) = 0
x = 2
Hp = {(2,-1)} (a)
16) bil pertama = a
bil kedua = b
a + b = 2
2a + 5 = -1
penyelesaian
2a + 5 = -1
2a = -1 - 5
2a = -6
a = -3
substitusi
a + b = 2
-3 + b = 2
b = 2 + 3
b = 5
jumlah kuadrat:
a² + b² = (-3)² + 5²
= 9 + 25
= 34 (c)
semoga membantu ya :)