dewiilia
N = -9/2 - √2001/2 n = √2001/2 - 9/2 Solve for n over the real numbers: 500 (n^2+9 n-480) = 0 Divide both sides by 500: n^2+9 n-480 = 0 n = -9 ±√(9^2-4 (-480)) /2 = (-9±√(81+1920))/2 = (-9±√(2001))/2: n = (-9+√(2001))/2 atau n = (-9-√(2001))/2
500 (n² + 9n + 480)
*** a . b = koefisien n² . koefisien
= 1 . 480 = 480
*** a + b = koefisien n
= 9
****** a = ..., b = ...
500 (n + a)(n + b)
Tar, ane lgi bingung. heheh, coba agan slsein sndiri
Smoga mmbntu... :)
n = √2001/2 - 9/2
Solve for n over the real numbers:
500 (n^2+9 n-480) = 0
Divide both sides by 500:
n^2+9 n-480 = 0
n = -9 ±√(9^2-4 (-480)) /2 = (-9±√(81+1920))/2 = (-9±√(2001))/2:
n = (-9+√(2001))/2
atau
n = (-9-√(2001))/2
begini gan