In Wisconsin in 2001 approximately 1300 000 cows produced 2.21 x ( dziesięc do potęgi dziesiątej) lb.... Question from @Bella1013

September 2018 1 18 Report

In Wisconsin in 2001 approximately 1300 000 cows produced 2.21 x ( dziesięc do potęgi dziesiątej) lb milk. On average how much milk did each cow produce?

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C=1 300 000 = 1,3 *10⁶ cows

M= 22,1*10⁹ = lb milk

A= average milk production

$A=\frac{M}P{}\ = \frac{22,1*10^9}{1,3*10^6}=\frac{22,1*10^3}{1,3}=\frac{22100}{1,3}=17000=17*10^3\ lb$

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