Ile wynosi wysokość stożka o objętości 81 π i obwodzie podstawy 18 π?
V=81π
l=2 πr
18 π=2 πr|:2
9 π= πr|; π
r=3
V= πr2xH
81 π= π9xH
81 π=9 πxH|;9 π
H=9
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V=81π
l=2 πr
18 π=2 πr|:2
9 π= πr|; π
r=3
V= πr2xH
81 π= π9xH
81 π=9 πxH|;9 π
H=9