Odpowiedź:
R = 10 Ω,
L = 0,05 H,
C = 25 μF=25*10⁻⁶F
uO = 30 V,
ω =1000 s⁻¹
Xl=ωL
Xl=1000s⁻¹*0,05H=50Ω
Xc=1/ωC
Xc=1/1000s⁻¹*25*10⁻⁶F=40Ω
Z=√R²+(Xl-Xc)²
Z=√10²+(50-40)²
Z=14,14Ω
i=u0/Z
i=30V/14,14Ω
i=2,12A
I=i/√2
I=2,12A/1,41
I=1,5A
Wyjaśnienie:
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Odpowiedź:
R = 10 Ω,
L = 0,05 H,
C = 25 μF=25*10⁻⁶F
uO = 30 V,
ω =1000 s⁻¹
Xl=ωL
Xl=1000s⁻¹*0,05H=50Ω
Xc=1/ωC
Xc=1/1000s⁻¹*25*10⁻⁶F=40Ω
Z=√R²+(Xl-Xc)²
Z=√10²+(50-40)²
Z=14,14Ω
i=u0/Z
i=30V/14,14Ω
i=2,12A
I=i/√2
I=2,12A/1,41
I=1,5A
Wyjaśnienie: