Question

Ile wynosi opór 100 m drutu miedzianego o średnicy 1 mm?

Answer 1

Answer 2

dane:

l = 100 m = 10² m

d = 1 mm

r = d/2 = 0,5 mm = 0,0005 m = 5 *10⁻⁴ m

ρ = 1,72 *10⁻⁸Ωm

szukane:

R = ?

 

R = ρ * l/s

     s = πr² 

R = 1,72 * 10²/[3,14 *(5*10⁻⁴)²] = 0,219 *10 Ω

R = 2,19 Ω

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