Ile waży 5 moli wodorotlenku wapnia?
M Ca(OH)2 = 40 + 32 + 2 = 74 g/mol
1 mol Ca(OH)2 - 74 g
5 moli Ca(OH)2 - x
x = 5 * 74
x = 370 g Ca(OH)2
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M Ca(OH)2 = 40 + 32 + 2 = 74 g/mol
1 mol Ca(OH)2 - 74 g
5 moli Ca(OH)2 - x
x = 5 * 74
x = 370 g Ca(OH)2