Ile to wynosi a)10 + (x-3) b) (8+x)*8
a)
10+(x-3)=10+x-3=7+x
b)
(8+x)*8=64+8x
10+(x-3)=7+x
(8+x)*8= 64+8x
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a)
10+(x-3)=10+x-3=7+x
b)
(8+x)*8=64+8x
10+(x-3)=7+x
(8+x)*8= 64+8x