Ile to jest {x-2x=7
{3x+3y=15
2układ. {6x+y-7
{-3x+2y=16 Znam jedynie metodą przeciwnych wspólczynników
a i metodą PODSTAWIANIA
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{x-2x=7
{3x+3y=15
x = 7+2y
3(7+2y)+3y = 15
x = 7+2y
21+6y+3y = 15
x = 7+2y
9y = 15-21
x = 7+2y
9y = -6 /:9
x = 7+2y
y = -6/9 = -2/3
x = 7+2·(-2/3)
y = -2/3
x = 7-4/3
y = -2/3
x = 7-1 1/3 = 5 2/3
y = -2/3
x = 5 2/3
y = -2/3
_________________________________
{6x+y-7
{-3x+2y=16
y = 7-6x
-3x+2(7-6x) = 16
y = 7-6x
-3x+14-12x = 16
y = 7-6x
-15x = 16-14
y = 7-6x
-15x = 2 /:(-15)
y = 7-6x
x = -2/15
y = 7-6·(-2/15)
x = -2/15
y = 7+12/15 = 7+4/5
x =-2/15
y = 7 4/5
x = -2/15