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l=2πr
6,28*4=25,12
100/25,12=3 r ileśtam
prawie 4,ale pełne 3
l=2πr=8π cm=25,12cm
1m/25,12cm=100cm/25,12cm=3,98
Odp.: 3 obręcze
L≈2×3,14×r
L≈6,28×4cm
L≈25,12cm
100:25,12=3 i 2464/2512
czyli 3