Question

Ile moli siarczanu (VI) magznezu zawiera 1,5kg tego zwiazku

Answer 1

M MgSO4=120g/mol

120g MgSO4-----1mol

1500g MgSO4-----xmoli

x = 12,5mola  

Answer 2

m (masa) MgSO₄ = 24g + 32g + 4*16g= 120g 

1,5 kg= 1500g

 

skoro:

1 mol MgSO₄----------ma masę-----120g

to X moli MgSO₄------ma masę-----1500g

 

X= 1500g * 1 mol : 120g = 12,5 molaMgSO₄