Ile moli mydla powstanie w reakcji 120g wodorotlenku sodu z kwasem stearynowym.
mNaOH=40u
C17H35COOH + NaOH ---> C17H35COONa + H2O
40g NaOH ----- 1mol mydła
120gNaOH ------ xmoli mydła
x = 3mole mydła
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
mNaOH=40u
C17H35COOH + NaOH ---> C17H35COONa + H2O
40g NaOH ----- 1mol mydła
120gNaOH ------ xmoli mydła
x = 3mole mydła