ile moli glinu potrzeba do otrzymania 16g Al2O3
Mmol=2*27+3*16=54+48=103g/mol2mole-103gxmoli-16gx=0,31mola
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Mmol=2*27+3*16=54+48=103g/mol
2mole-103g
xmoli-16g
x=0,31mola