Ile moli chlorku sodu zawiera 50 g tego związku?
NaCl=m Na + m Cl= 23g+ 35,5 g = 58,5g
1 mol NaCl - 58,5 gx moli NaCl - 50 g
x=0,85 mola NaCl
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NaCl=m Na + m Cl= 23g+ 35,5 g = 58,5g
1 mol NaCl - 58,5 g
x moli NaCl - 50 g
x=0,85 mola NaCl