Ile miedzi zawiera 1t rudy(93%CuS)?
Dane:mrudy=1t=1000kg%CuS=93%mCuS=96g/molmCu=64g/molObliczyć:M[CuS]=?M[Cu]=?Wyliczamy na proporcje.1000kg---------100%xkg-------93%
xkg=(1000kg*93%)/100%xkg=930kg CuSNo i wyliczamy z tego masę miedzi.930kg CuS--------96g/molxkgCu------------64g/molxkgCu=(930kg*64g/mol)/96g/molxkgCu=620kgCuPozdrawiam,Stasiek593.
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Dane:
mrudy=1t=1000kg
%CuS=93%
mCuS=96g/mol
mCu=64g/mol
Obliczyć:
M[CuS]=?
M[Cu]=?
Wyliczamy na proporcje.
1000kg---------100%
xkg-------93%
xkg=(1000kg*93%)/100%
xkg=930kg CuS
No i wyliczamy z tego masę miedzi.
930kg CuS--------96g/mol
xkgCu------------64g/mol
xkgCu=(930kg*64g/mol)/96g/mol
xkgCu=620kgCu
Pozdrawiam,
Stasiek593.