Ile gramów wody powstanie z 400g wodoru w reakcji syntezy.
mH2=2u
mH2O=18u
2H2 + O2 ---> 2H2O
2*2g H2 ------- 2*18g H2O
400g H2 ------- xgH2O
x = 3600g H2O
2H2+O2---->2H2O
400g x
4mH=4u
2mH2O=36u
400g---------4u
x---------------36u
x=3600g wody
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mH2=2u
mH2O=18u
2H2 + O2 ---> 2H2O
2*2g H2 ------- 2*18g H2O
400g H2 ------- xgH2O
x = 3600g H2O
2H2+O2---->2H2O
400g x
4mH=4u
2mH2O=36u
400g---------4u
x---------------36u
x=3600g wody