Ile gramów tlenu zawierają 2 mole tlenku siarki (VI)
M(SO3)=32g/mol+3*16g/mol=80g/mol
1mol----------------48g
2mol----------------xg
xg=2mol*48g/1mol
xg=96g
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M(SO3)=32g/mol+3*16g/mol=80g/mol
1mol----------------48g
2mol----------------xg
xg=2mol*48g/1mol
xg=96g