Ile gramów soli powstanie po wrzuceniu 12 g magnezu do roztworu zawierajacego 24,5g kwasu siarkowego?
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12g Mg = 12/24 = 0,5 mola Mg
24,5g H2SO4 = 24,5/98 = 0,25 mola H2SO4
Mg + H2SO4 ------------------> MgSO4 + H2↑
1 mol...............98g ............................. 120g (Mg w nadmiarze i decyduje
H2SO4)
24,5g..............................x
-----------------------------------
x = 30g MgSO4
Powstanie 30g MgSO4.
Semper in altum
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