Ile gramów potasu znajduje się w 420g wodorotlenku potasu?.
Na dzisiaj prosze.
Masa KOH wynosi 56g/mol
56 - 39
420 - x
x=420*39/56 = 292,5g
mol KOH=39+16+1=56g420/56=7,5 mola KOH stanowi 420g mol K = 39g7,5*39=292,5g
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Masa KOH wynosi 56g/mol
56 - 39
420 - x
x=420*39/56 = 292,5g
mol KOH=39+16+1=56g
420/56=7,5 mola KOH stanowi 420g
mol K = 39g
7,5*39=292,5g