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80g-------98g
0,4g-----0,49g
50cm3=0,05dm3
1molH2SO4-98g
0,1molH2SO4-x
x=9,8g
9,8gH2SO4-1dm3
x-0,05dm3
x=0,49gH2SO4
98g-100%
0,49g-x
x=0,5%
80gNaOH-100%
x-0,5%
x=0,4gNaOH
w 10cm3 musi byc 0,4g
zakladajac, ze rozpuszczasz w wodzie dH2O=1g/cm3
9,6gr-0,4gNaOH
500gr-x
x=20,83gNaOH - tyle go potrzebujesz :D