6 HCl + Al₂O₃ -> 2 AlCl₃ + 3 H₂O
M HCl = 1g+35,5g=36,5g
36,5g*6=219g
M Al₂O₃ = 2*27g + 3*16g = 54g + 48g = 102g
219g - 102g
21,9g - 10,2g
Odp. Potreba 21,9g kwasu solnego.
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xg kwasu-10,2g tlenku glinu
219g- 102g
x=21,9 g kwasu potrzeba
6 HCl + Al₂O₃ -> 2 AlCl₃ + 3 H₂O
M HCl = 1g+35,5g=36,5g
36,5g*6=219g
M Al₂O₃ = 2*27g + 3*16g = 54g + 48g = 102g
219g - 102g
21,9g - 10,2g
Odp. Potreba 21,9g kwasu solnego.